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7x^2+11x-18=0
a = 7; b = 11; c = -18;
Δ = b2-4ac
Δ = 112-4·7·(-18)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-25}{2*7}=\frac{-36}{14} =-2+4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+25}{2*7}=\frac{14}{14} =1 $
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